InterviewSolution
Saved Bookmarks
| 1. |
When a battery connected across a resistor of `16 Omega`, the voltage across the resistor is 12 V. When the same battery is connected across a resistor of `10 Omega`, voltage across it is 11 V. The internal resistance of the battery (in ohm) isA. `(10)/(7)`B. `(20)/(7)`C. `(25)/(7)`D. `(30)/(7)` |
|
Answer» Correct Answer - B Here, VltE `lt`E = V + lr For first case, `E=12+(12)/(16)r ` For second case, `E=11+(11)/(10)r From Eqs. (i) and(ii),we get `12+(12)/(16)r=11+(11)/10rrArr r==20/7Omega` |
|