When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L +l). The elastic potential energy stored in the extended wire is:

When a block of mass M is suspended by a long wire of length L, the le

1.	When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L +l). The elastic potential energy stored in the extended wire is:
Answer» `(1)/(2) MGL` Mgl MgL `(1)/(2) Mgl` SOLUTION :Elastic potential energy `=(1)/(2) xx` (force) `xx` (INCREASE in length) `=(1)/(2) xx mg xx (L + l -L)` `=(1)/(2) mgl`