When a body is thrown up in a lift with a velocity `u` relative to the lift, the time of flight is found to be `t`. The acceleration with which the lift is moving up isA. `((u-g t))/(t)` upwardsB. `((u-g t))/(t)` downwardsC. `((2u-g t))/(t)` upwardsD. `((2u-g t))/(t)` downwards

When a body is thrown up in a lift with a velocity `u` relative to the

1.	When a body is thrown up in a lift with a velocity `u` relative to the lift, the time of flight is found to be `t`. The acceleration with which the lift is moving up isA. `((u-g t))/(t)` upwardsB. `((u-g t))/(t)` downwardsC. `((2u-g t))/(t)` upwardsD. `((2u-g t))/(t)` downwards
Answer» Correct Answer - C

Discussion

No Comment Found

Related InterviewSolutions

Two partides. are thrown from the same point in the same vertical plane, as shown in figure simultaneously. Then indicate the correct statements : A. Time of flight for B is less than that of AB. Projection speed of B is greater than that of AC. Horizontal component of velocities of B is greater than that of AD. The vertical component of velocities of both A and B are always equal throughout the duration for which both the particles in air
A stone is released from an elevator going up with an acceleration a. The acceleration of the stone after the release isA. a upwardB. (g - a) upwardC. (g - a) downwardD. g downward
A hollow vertical cylinder of radius R and height h has smooth internal suface. A small particle is placed in contact with the inner side of the upper rim at a point P. It is given a horizontal speed `v_(0)` tangential to rim. It leaves the lower rim point Q vertically below P. The number of revolutions made by the particle will:A. `h/(2piR)`B. `(v_(0))/(sqrt(2gh))`C. `(2piR)/(h)`D. `(v_(0))/(2piR)(sqrt((2h)/(g)))`
A block is kept on the floor of an elevator. The elevator starts descending with an acceleration of 12`m//s^(2)` the displacement of the block during `1^(st)` one second wth respect to elevator is-A. 1m downwardsB. 1 m upwardsC. 5m downwardsD. zero meter.
A rod of length I leans by its upper end against a smooth vertical wall, while its other end leans against the floor. The end that leans against the wall moves uniformly downward. Then: A. The other end also moves uniformlyB. The speed of other end goes on decreasingC. The speed of other end goes on increasingD. The speed of other end first decreases and thenincreases
A body travelling along a straight line , one thired of the total distance with a velocity ` 4 ms^(-1)`. The remaining part of the distance was covered with a velocity ` 2 ms^(-1)` for half the time and with velocity ` 6 ms^(-1)` for the other half of time . What is the mean velocity averaged over te whle time of motin ?A. 5m/sB. 4m/sC. `4.5m//s`D. `3.5m//s`
An aeroplane moving horizontally from west to east with some velocity and with an acceleration `5m//s^(2)` drops a food packet at some instant. Then:A. The path of the packet is parabolic with respect to groundB. A person sitting on the aeroplane shall see the packet is always vertically below the plane.C. With respect to plane the packet travels in a straight line making an angle `"tan"^(1) (1//2)` east of vertical.D. With respect to plane the packet travels in a straight line making an angle `"tan" ^(-1) (1//2)` east of vertical.
A particle has an initial velocity of `9m//s` due east and a constant acceleration of `2m//s^(2)` due west. The displacement coverd by the particle in the fifth second of its motion is :A. zeroB. 0.5mC. 2mD. None
A plane is inclined at an angle `30^(@)` with horizontal. The component of a vector `vec(A)= -10k` perpendicular to this plane is: (here z-direction is vertically upwards)A. `5 sqrt(2)`B. `5 sqrt(3)`C. `5`D. `2.5`
Two particles, 1 and 2, move with constant velocities `v_1` and `v_2`. At the initial moment their radius vectors are equal to `r_1` and `r_2`. How must these four vectors be interrelated for the particles to collide?A. `(vecr_(1)-vecr_(2))/(|vecr_(1)-vecr_(2)|)=(vecv_(1)-vecv_(2))/(|vecr_(1)-vecv_(2)|`B. `(vecr_(1)-vecr_(2))/(|vecr_(1)-vecr_(2)|)=(vecv_(2)-vecv_(1))/(|vecr_(2)-vecv_(1)|`C. `(vecr_(1)-vecr_(2))/(|vecr_(2)-vecr_(1)|)=(vecv_(2)-vecv_(1))/(|vecr_(1)-vecv_(2)|`D. None of these

When a body is thrown up in a lift with a velocity `u` relative to the lift, the time of flight is found to be `t`. The acceleration with which the lift is moving up isA. `((u-g t))/(t)` upwardsB. `((u-g t))/(t)` downwardsC. `((2u-g t))/(t)` upwardsD. `((2u-g t))/(t)` downwards

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment