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When a body is thrown up in a lift with a velocity `u` relative to the lift, the time of flight is found to be `t`. The acceleration with which the lift is moving up isA. `(u-"gt")/(t)`B. `(u+"gt")/(t)`C. `(2u-"gt")/(t)`D. `(u)/(t)-2g` |
Answer» `(2u)/(g+a)=t rArr a =(2u)/(t)-g` | |