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When a body of mass `1.0 kg` is suspended from a certain light spring hanging vertically, its length increases by `5cm`. By suspending `2.0kg` block to the spring and if the block is pulled through `10cm` and released, the maximum velocity of it in `m//s is (g = 10 m//s^(2))`A. `0.5`B. `1`C. `2`D. `4` |
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Answer» Correct Answer - B `K = (mg)/(x) , T = 2pi sqrt((m)/(K)), omega = sqrt((K)/(m)), V_(max) = A omega` |
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