When a body of mass .m., density d_(B) is suspended from a wire, its elongation is .e. when the body is in air. If the body is completely immersed in a non-viscous liquid of density d_(l) when its elongation is

When a body of mass .m., density d_(B) is suspended from a wire, its e

1.	When a body of mass .m., density d_(B) is suspended from a wire, its elongation is .e. when the body is in air. If the body is completely immersed in a non-viscous liquid of density d_(l) when its elongation is
Answer» Solution : `F=W_(a)=MG` `F^(1)=W_(l)=mg(1-(d_(l))/(d_(B)))` as `e=(Fl)/(AY)` e `alpha` F (as `l`, A, Y are same in both cases) `(d^(1))/(e )=(F^(1))/(F)=(cancel(mg)(1-(d_(l))/(d_(B))))/(cancel(mg))rArr e^(1)=e(1-(d_(l))/(d_(B)))`