1.

When a centimeter thick surface is illuminated with light of wavelength `lamda`, the stopping potential is V. When the same surface is illuminated by light of wavelength `2lamda`, the stopping potential is `(V)/(3)`. Threshold wavelength for the metallic surface isA. `(4lambda)/3`B. `4lambda`C. `6lambda1`D. `(8lambda)/3`

Answer» Correct Answer - B
`(hC)/lambda=phi+eV`..(i)
`(hC)/(2lambda)=phi+(eV)/3`..(ii)
`3xxII-IrArr (3/2-1)(hc)/lambda=2phi rArr phi=(hc)/(4lambda)`
`therefore lambda_(th)=4lambda`


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