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When a certain number is divided by 52, the remainder is 49. When the same number is divided by 13, the remainder is x. What is the value of \(\sqrt{5x-1}\) ?1. 112. 63. 74. 8 |
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Answer» Correct Answer - Option 3 : 7 Given: First Divisor = 52 First Remainder = 49 Second Divisor = 13 Second Remainder = x Concept Used: Dividend = Divisor × Quotient + Remainder Calculation: let the dividend be D Quotient be Q1 and Q2 According to question, D = Q1 × 52 + 49 D = Q2 × 13 + x Since 13 is a multiple of 52, we can assume that D is divided by 13 it also leaves the remainder 49, but 49 can be further divided by 13 It leaves the remainder 10 This remainder 10 will be equal to x ⇒ \(√{5x-1}\) = \(√{5 \times 10 - 1}\) ⇒ √49 = 7 ∴ The value \(√{5x-1}\) is 7 |
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