When a circular coil of radius 1m and 100turns is rotated in a hor

1.	When a circular coil of radius 1m and 100turns is rotated in a horizontal uniform magnetic field, the peak value of emf. Induced is 100v. The coil is unwound and the rewound into circular coil of radius 2m. If it is rotated , now with the same speed, under similar conditions, the new peak value of emf developed isAns- 200v
Answer» A coil having N turns and area A rotates in a uniform magnetic field B with angular velocity ω, Then the peak value of the emf (V_max) induced in the coil is given by (V_max) = NABω Now the fact is that the area of the coil in the 2nd case is 4A since the radius is doubled. But the number of turns will be N/2 in the second case since the length of the wire required for a turn is doubled. If V₁ and V₂ are the peak values of the emf in the two cases, We have V₁/V₂ = 100 /V₂ = NABω / [(N/2)×(4A)Bω] Or, 100 /V₂ = ½ from which V₂ = 200 volt.

When a circular coil of radius 1m and 100turns is rotated in a horizontal uniform magnetic field, the peak value of emf. Induced is 100v. The coil is unwound and the rewound into circular coil of radius 2m. If it is rotated , now with the same speed, under similar conditions, the new peak value of emf developed isAns- 200v

Answer»

A coil having N turns and area A rotates in a uniform magnetic field B with angular velocity ω,
Then the peak value of the emf (V_max) induced in the coil is given by (V_max) = NABω

Now the fact is that the area of the coil in the 2nd case is 4A since the radius is doubled.

But the number of turns will be N/2 in the second case since the length of the wire required for a turn is doubled.

If V₁ and V₂ are the peak values of the emf in the two cases,

We have V₁/V₂ = 100 /V₂ = NABω / [(N/2)×(4A)Bω]
Or, 100 /V₂ = ½
from which
V₂ = 200 volt.

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