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When a force F acs on a body of mass m the acceleration product in the body is a . If htree equal forces `F_(1)=F_(2)=F_(3)=F` act on the same body as shown in figure the accleration produced is A. `(sqrt2 -1)a`B. `(sqrt2 +1)a`C. `sqrt2a`D. a |
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Answer» Correct Answer - A `a = (F)/(m), F_(R) = (sqrt(F_(1)^(2) +F_(2)^(2))-F_(3)),a^(1)=(F_(R))/(m)` |
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