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When a force of 10.0 N is exerted on the handle of a door, the door can be just opened. If the handle is a distance of 50 cm from the hinges find the torque applied on the door. |
Answer» <html><body><p></p>Solution :`tau = <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> <a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> theta = 0.50 xx 10.0 sin 90^(@)=5Nm`</body></html> | |