When a gas is bubbled through water at 298 K, a very dilute solution of the gas is obtained. Henry's law constant for the gas at 298 K is 100 kbar. If the gas exerts a partial pressure of 1 bar, the number of millimoles of the gas dissolved in one litre of water is

When a gas is bubbled through water at 298 K, a very dilute solution o

1.	When a gas is bubbled through water at 298 K, a very dilute solution of the gas is obtained. Henry's law constant for the gas at 298 K is 100 kbar. If the gas exerts a partial pressure of 1 bar, the number of millimoles of the gas dissolved in one litre of water is
Answer» `0.555` `5.55` `0.0555` `55.5` SOLUTION :`k_(H)` = 100 kbar, p = 1 bar `p=k_(H)xx` mole fraction Mole fraction `=(p)/(k_(H))=(1)/(100xx10^(3))=10^(-5)` Mole fraction `=("Mole of gas")/("Total moles")` Moles of water `=("Weight of water")/("MOLECULAR weight of water")` Weight of water= 1000g `(because 1000 mL = 1000g)` Moles `=(1000)/(18)=55.5` Mole fraction `= 10^(-5)=(x)/(55.5+x)` As `55.5 gt gt gt x`, thus neglecting x from denominator `10^(-5)=(x)/(55.5)rArr x = 55.5xx10^(-5)` moles or `55.5xx10^(-2)` millimoles = 0.555 millimoles.