InterviewSolution
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InterviewSolution
| 1. |
when a gun is at rest, then its initial momentum is zero. now when the bullet is fired, the iniial and final momentum should be same. we can write it as m_2+v_2+m_1v_1=0.Recoil velocity of gun is in opposite direction, so m_1v_1+\lbrack-m_2v_2\rbrack =0 because of opposite direction. this gives us m_1v_1=m_2v_2.But the direction of momentum is opposite so where does the negative sign goes |
| Answer» when a gun is at rest, then its initial momentum is zero. now when the bullet is fired, the iniial and final momentum should be same. we can write it as m_2+v_2+m_1v_1=0.Recoil velocity of gun is in opposite direction, so m_1v_1+\lbrack-m_2v_2\rbrack =0 because of opposite direction. this gives us m_1v_1=m_2v_2.But the direction of momentum is opposite so where does the negative sign goes | |