When a hydrogen atom is excited from ground state to first excited state, thenA. its kinetic energy increased by `20 eV`B. its kinetic energy dereased by `10.2 eV`C. its potential energy increased by `20.4 eV`D. its angular momentum increased by `1.05 xx 10^(-34) J s`

When a hydrogen atom is excited from ground state to first excited sta

1.	When a hydrogen atom is excited from ground state to first excited state, thenA. its kinetic energy increased by `20 eV`B. its kinetic energy dereased by `10.2 eV`C. its potential energy increased by `20.4 eV`D. its angular momentum increased by `1.05 xx 10^(-34) J s`
Answer» Correct Answer - B::C::D Ground state `n = 1` First excited state `n = 2` `KE = (1)/(4 pi epsilon_(0)) (e^(2))/(2 r) (z = 1)` `KE = (14.4 xx 10^(-10))/(2 r) eV` Now `r = 0.53 n^(2) Å (z = 1)` `(KE)_(1) = (14.4 xx 10^(-10))/(2 xx 0.53 xx 10^(-10)) eV = 13.58 eV` `(KE)_(2) = (14.4 xx 10^(-10))/(2 xx 0.53 xx 10^(-10) xx 4) eV = 3.39 eV` `KE` decrease by `10.2 eV` Now `PE = (-1)/(4 pi epsilon_(0)) (e^(2))/(r) = (-14.4 xx 10^(-10))/( r) eV` `(PE)_(1) = (-14.4 xx 10^(-10))/(0.53 xx 10^(-10)) eV = - 27.1 eV` `(PE)_(2) = (-14.4 xx 10^(-10))/(0.53 xx 10^(-10) xx 4) eV = - 6.79 eV` `PE` increase by `20.4 eV` Now, angular momentum, `L = mvr= (nh)/(2 pi)` `L_(2) - L_(1) = (nh)/(2 pi) = (6.6 xx 10^(-34))/(6.28) = 1.05 xx 10^(-34) J s`

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When a hydrogen atom is excited from ground state to first excited state, thenA. its kinetic energy increased by `20 eV`B. its kinetic energy dereased by `10.2 eV`C. its potential energy increased by `20.4 eV`D. its angular momentum increased by `1.05 xx 10^(-34) J s`

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