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When a long spring is stretched by 2cm, its potential energy is U. If the spring is stretched by 10cm, the potential energy stored in it will beA. 25UB. U/5C. 5UD. 10U |
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Answer» Correct Answer - A `U prop x^(2)` `(U_(2))/(U_(1))=(x_(2)^(2))/(x_(1)^(2))rArr (U_(2))/(U)=10(2)^(2)=25 rArr U_(2)=25U_(1)=25U` |
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