When a man of mass 60 kg sits inside a car, the centre of gravity of the car descends by 0.3 cm. If the mass of the car is 1000 kg, calculate the frequency of oscillation of the empty car.

When a man of mass 60 kg sits inside a car, the centre of gravity of t

1.	When a man of mass 60 kg sits inside a car, the centre of gravity of the car descends by 0.3 cm. If the mass of the car is 1000 kg, calculate the frequency of oscillation of the empty car.
Answer» Solution :Frequency of OSCILLATION of the car, `N=1/(2pi)SQRT(k/m)`. The force constant of the spring of the car, `k=F/x=(60xx9.8)/(0.3xx10^(-2))=196xx10^(3)N*m^(-1)` `therefore"Frequency",n=1/(2xx22/7)sqrt((196xx10^(3))/1000)` = `(14xx7)/44=2.23s^(-1)`.