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When a mass M is attached to the spring of force constant K, then the spring stretches by l . If the mass oscillates with a amplitude l. What will be maximum p.e stored in the spring |
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Answer» We know that when the mass is suspended, the spring stretches by l, then Mg=kl. And energy stored in spring = kl2/2 = (kl)l/2 = Mgl/2. When the spring oscillates at the maximum displacement, additional potential energy stored = kl2/2 = Mgl/2. Therefore maximum potential energy or total potential energy = Mgl/2+Mgl/2 = Mgl |
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