When a metal rod M is dipped into an aqueous colourless concentrated solution of compound N the solution turns light blue.Addition of aqueous NaCl to the blue solution gives a white precipitate O.Addition of aqueous NH_(3) dissolves O and gives an intense blue solution. The metal rod M is :

When a metal rod M is dipped into an aqueous colourless concentrated s

1.	When a metal rod M is dipped into an aqueous colourless concentrated solution of compound N the solution turns light blue.Addition of aqueous NaCl to the blue solution gives a white precipitate O.Addition of aqueous NH_(3) dissolves O and gives an intense blue solution. The metal rod M is :
Answer» `Fe` `Cu` `Ni` `Co` Solution :`Cu(M)+AgNO_(3)(N)`(queous colourless solution) `to` Resultant solution contains `Cu(NO_(3))_(2)` (blue solution) and `AgNO_(3)` (colourless solution) Note: Here it is considered that COMPLETE `AgNO_(3)` is not utilized in the reaction. `AgNO_(3)(aq)+NACL(aq) to AgCl DARR`(white) `(O)+NaNO_(3)` Solution containing white ppt. of `AgCl` also contains `Cu(NO_(3))_(2)` which DEVELOPED deep blue colouration with aqueous `NH_(3)` solution `AgCl darr ("white")+2NH_(3)(aq.) to [Ag(NH_(3))_(2)]^(+)` `Cu(NO_(3))_(2)(aq.)+4NH_(3) (aq.) to [Cu(NH_(3))_(4)](NO_(3))_(2)` (deep blue solution) So, Metal rod `M` is `Cu`. The compound `N` is `AgNO_(3)` and the final solution contains `[Ag(NH_(3))_(2)]^(+)` and `[Cu(NH_(3))_(4)]^(2+)`