When a metal rod M is dipped into an aqueous colourless concentrated solution of compound N, the solution turns light blue. Addition of aqueous `NaCl` to the blue solution gives a white precipitate O. Addition of aqueous `NH_(3)` dissolves O and gives an intense blue solution. The compound N isA. `AgNO_(3)`B. `Zn(NO_(3))_(2)`C. `Al(NO_(3))_(3)`D. `Pb(NO_(3))_(2)`

When a metal rod M is dipped into an aqueous colourless concentrated s

1.	When a metal rod M is dipped into an aqueous colourless concentrated solution of compound N, the solution turns light blue. Addition of aqueous `NaCl` to the blue solution gives a white precipitate O. Addition of aqueous `NH_(3)` dissolves O and gives an intense blue solution. The compound N isA. `AgNO_(3)`B. `Zn(NO_(3))_(2)`C. `Al(NO_(3))_(3)`D. `Pb(NO_(3))_(2)`
Answer» Correct Answer - A `Cu(M) +AgNO_(3) ( "aqueous colorless solution ") rarr "Resultant solution " underset((N)(blue solution)")((Cu(NO_(3))_(2)+AgNO_(3)))` Note `:` Here it is considered that complete `AgNO_(3)` is not utilized in the reaction `AgNO_(3)+NaClrarrunderset((O)(whiter ppt.)")(AgCldarr+NaNO_(3))` Solution containing white ppt. of AgCl also contains `Cu(NO_(3))_(2)` which developed deep blue colouration with aqueous `NH_(3)` solution . `AgCldarr ("white")+2NH_(3)(aq). rarr [Ag(NH_(3))_(2)]^(+)` `Cu(NO_(3))_(2)(aq.)+4NH_(3)(aq.) rarr underset("(deep blue coloration)")([Cu(NH_(3))_(4)](NO_(3))_(2)` So, Metal rod M is Cu. The compound N is `AgNO_(3)` and the final solution contains `[Ag(NH_(3))_(2)]^(+)` and `[Cu(NH_(3))_(4)]^(2+)`

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