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Amongst the following, the lowest degree of paramgnetism per mole of the compound at `298 K` will be shown byA. `MnSO_(4).4H_(2)O`B. `CuSO_(2)5H_(2)O`C. `FeSO_(4).6H_(2)O`D. `NiSO_(4).6H_(2)O` |
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Answer» Correct Answer - B `Mn^(2+)` in `MnSO_(4).4H_(2)O` has `d^(5)` configuration ( five unpaired eletrons) `: Cu^(2+` in `CuSO_(4).5H_(2)O` has `d^(9)` configuration ( one unpaired electron) , `Fe^(2+)` in `FeSO_(4).6H_92)O` has `d^(6)` configuration ( four unpaired electron ) , and `Ni^(2+)` in `NiSO_(4). 6 H_(2)O` has `d^(8)` configuration ( two unpaired electron) . Thus `CuSO_(4).5H_(2)O` has lowest degree of paramagnetism. |
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