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When a metallic sphere is released from the surface of water filled in a container of uniform area of cross section it is found to reach the bottom of the container in 2 s.If the density of the material of the sphere is 4.9 g cm^(-3), calculate the pressure exerted by the liquid at the bottom of the container. Assume that only gravitational force and up-thrust act on the body. |
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Answer» Solution :`(i) V_(0)XX d_(0) xx a= V_(10)xx d_(1)xxg -V_(0)xx d_(1)xx G` `A=(g(d_(0)-d_(1)))/(d_(0))` `S=ut+(1)/(2) at^(2)` P=hdg (ii) 15,2880 Pa |
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