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| 1. |
When a metallic surface is illuminated with radiation of wavelength `lambda`, the stopping potential is `V`. If the same surface is illuminated with radiation of wavelength `2 lambda` , the stopping potential is `(V)/(4)`. The threshold wavelength surface is :A. `5lambda`B. `(5)/(2)lambda`C. `3lambda`D. `4lambda` |
| Answer» Correct Answer - C | |