1.

When a metallic surface is illuminated with radiation of wavelength `lambda`, the stopping potential is `V`. If the same surface is illuminated with radiation of wavelength `2 lambda` , the stopping potential is `(V)/(4)`. The threshold wavelength surface is :A. `5lambda`B. `(5)/(2)lambda`C. `3lambda`D. `4lambda`

Answer» Correct Answer - C


Discussion

No Comment Found

Related InterviewSolutions