When a mixture of NaBr and NaCl is separately digested with H_2SO_4 all the halogens are expelled and Na_2SO_4 is formed quantitatively with a particular mixture, it was found that the weight of Na_2SO_4 obtained was precisely the same as the weight of NaBr+NaCl mixture taken. Calculate the ratio of the weight of NaCl and NaBr in the mixture.

When a mixture of NaBr and NaCl is separately digested with H_2SO_4 al

1.	When a mixture of NaBr and NaCl is separately digested with H_2SO_4 all the halogens are expelled and Na_2SO_4 is formed quantitatively with a particular mixture, it was found that the weight of Na_2SO_4 obtained was precisely the same as the weight of NaBr+NaCl mixture taken. Calculate the ratio of the weight of NaCl and NaBr in the mixture.
Answer» SOLUTION :Let the weight of `NaCl` be x g and the weight of NABR be y g. ,brgt We have to CALCULATE `(x)/(y)` `2NaCl-=Na_2SO_4` `2xx58.5g of NaCl-=142g of Na_2SO_4` `x g of NaCl-=(142)/(2xx58.4)XX x g of Na_2SO_4` `2NaBr-=Na_2SO_4` `2xx103g of NaBr-=142 g of Na_2SO_4` `y g of NaBr-=(142)/(2xx103)xx x g of Na_2SO_4` `therefore(142X)/(2xx58.5)+(142x)/(2xx103)=x+y` `1.21x-x=y-0.69y` `0.21x=0.31y` `(x)/(y)=(0.31)/(0.21)=1.475` The ratio of weights of `NaCl:NaBr` is `1.476:1`