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When a monochromatic light ray is incident on a medium of refracive index`mu`with angle of incidence `theta_(1)`,the angle of refraction is `theta_(r).`if `theta_(i)` is changed slightly by`Deltatheta_(i)`,then the corresponding change in `theta_(r)`will be-A. `Delta Theta_(i)`B. `muDeltatheta_(i)`C. `(1)/(mu).cos theta_(1)/(cos theta_(r)).Delta theta_(i)`D. `mu.sin theta_(1)/(sin theta_(r)).Delta theta_(i)` |
Answer» Correct Answer - C `mu=(sintheta_(i))/(sintheta_(r))` `sintheta_(r)=(1)/(mu)sintheta_(i)` Differentiate the equation with respect to`theta_(i)` `costheta_(r)""(d theta_(r))/(d theta_(i))=(1)/(mu) costheta_(i)` `d theta_(r)=(1)/(mu)(costheta_(i))/(costheta_(r))d theta_(r)` `Delta theta_(r)=(1)/(mu)(costheta_(i))/(costheta_(r))d theta_(r)Delta theta_(i)` |
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