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When a motor cyclist takes a U-turn in 4s what is the average velocity of the motor cyclist? |
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Answer» Solution :When the MOTOR cyclist TAKES a U-turn, angular displacement, `theta = pi rad and t = 4 s `. The AVERAGE angular velocity, `omega = (theta)/(t)=(pi)/(4) = 7.855xx10^(-1) = 0.7855rads^(-1)`. |
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