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When a motor cyclist takes a `U-turn` in `4s` what is the average angular velocity of the motor cyclist. |
Answer» When the motor cyclist takes a U-turn, angular displacement, `theta=pi` rad and `t=4s`. The average angular velocity, `omega=theta/t,alpha_(av)=(Deltaomega)/(Deltat)` `omega=(d theta)/dt,alpha=(d omega)/dt=(d^(2)theta)/dt^(2)=omega(domega)/(d theta)` int d theta=int omega dt, int d omega=int alpha dt,int alpha d theta=int omega d omega` |
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