When a motorcyle moving with a unifrom speed 11 m/s is at a distance 24 m from a car, the car starts from rest and moves with a uniform acceleration 2 m//s^(2) away from the motorcyle. If the car begins motion at t = 0, time at which the motorcyle will overtake the car is t = ?

When a motorcyle moving with a unifrom speed 11 m/s is at a distance 2

1.	When a motorcyle moving with a unifrom speed 11 m/s is at a distance 24 m from a car, the car starts from rest and moves with a uniform acceleration 2 m//s^(2) away from the motorcyle. If the car begins motion at t = 0, time at which the motorcyle will overtake the car is t = ?
Answer» 8 sec 6 sec 3 sec 1.5 sec Solution :Let motorcycle meets the car after time t. For motorcycle: `x = 11 t + 24` For car: `x = (1)/(2) at^(2)` `24 + 11 t = (1)/(2) xx 2 xx t^(2)` `t^(2) - 11 t - 24 = 0` `t = 3 sec`