When a motorcyle moving with a unifrom speed 11 m/s is at a distance 24 m from a car, the car starts from rest and moves with a uniform acceleration 2 m//s^(2) away from the motorcyle. If the car begins motion at t = 0, time at which the motorcyle will overtake the car is t = ?

When a motorcyle moving with a unifrom speed 11 m/s is at a distance 2

1.	When a motorcyle moving with a unifrom speed 11 m/s is at a distance 24 m from a car, the car starts from rest and moves with a uniform acceleration 2 m//s^(2) away from the motorcyle. If the car begins motion at t = 0, time at which the motorcyle will overtake the car is t = ?
Answer» <html><body><p>8 sec<br/>6 sec<br/><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> sec<br/><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.5 sec</p>Solution :Let motorcycle meets the car after time t. <br/> For motorcycle: `x = 11 t + 24` <br/> For car: `x = (1)/(2) at^(2)` <br/> `24 + 11 t = (1)/(2) xx 2 xx t^(2)` <br/> `t^(2) - 11 t - 24 = 0` <br/> `t = 3 sec`</body></html>