When a particle is performing linear SHM its K.E. is two times its P.E. at a position A and its P.E. is two times its K.E. at another positon B. Find the ratio of K.E at A to K.E at B.

When a particle is performing linear SHM its K.E. is two times its P.E

1.	When a particle is performing linear SHM its K.E. is two times its P.E. at a position A and its P.E. is two times its K.E. at another positon B. Find the ratio of K.E at A to K.E at B.
Answer» SOLUTION :T E at A=K.E. at `A+P.E. ` at A. But K.E. at `A=2` (P.E. at A) P.E at `A=1/2` (K.E. at A) T.E at `A=K.E`. At`A+1/2` (K.E. at A) `=3/2` K.E. at A Similarly T.E. at B= K.E. at B+P.E at B But P.E at B=2 (K.E.at B) T.E. at B=K.E. at B+2(K.E. at B) =3 K.E at B. By the PRINCIPLE of conservation of ENERGY T.E. at A=T.E. at `B=3/2` K.E. atA=3 K.E `""` at `B=(K.E. "at"A)/(K.E. "at"B)=2/1`