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When a particle oscillates simple harmonically, its kinetic energy varies periodically. If frequency of the particle is n, the frequency of the kinetic energy isA. 4 nB. nC. 2 nD. `n//2` |
Answer» Correct Answer - C `K.E,=(1)/(2) momega^(2) (A^(2)-x^(2))` `=(1)/(2) momega^(2) (A^(2)-A^(2) sin^(2)omegat)` `=(1)/(2) momega^(2)A^(2)(1-sin^(2)omega^(2)omegat)` `K.E.=(1)/(2)momega^(2)A^(2) ((1+cos2omegat))/(2)` `therefore` The frequency of its kinetic energy is `2omega` |
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