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When a polynomial f(x) is divided by (x – 3) and (x + 6), the respective remainders are 7 and 22. What is the remainder when f(x) is divided by (x – 3) (x + 6) ? (a) \(\frac{-5}{3}x+12\)(b) \(-\frac{7}{3}x+14\)(c) \(-\frac{5}{3}x+16\)(d) \(-\frac{7}{3}x+12\) |
Answer» (a) \(\frac{-5}{3}x+12\) The function f(x) is not known. Here, a = 3, b = – 6 A = 7, B = 22 [Refer to Key Fact 8] ∴ Required remainder = \(\frac{A-B}{a-b}x+\frac{Ba-Ab}{a-b}\) = \(\frac{7-22}{3-(-6)}x+\frac{22\times3-7\times(-6)}{3-(-6)}\) = \(\frac{-5}{3}x+12.\) |
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