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When a polynomial `p(x)` of degree 3 is divided by `3x^2-8x+5` quotient and remainder obtained are linear polynomial such that `p(1)=19` and `p(5/3)=25`. So,find the remainder polynomial. |
Answer» `f(x)=(3x^2-8x+5)(ax+b)+(c+d)` Put x=1 `p(1)=(3*1-8+5)(a+b)c+d=19` `c+d=19-(1)` Put x=-5/3 `p(5/3)=(3*25/9-8*5/3+5)(a5/3+b)+(c*5/3+d)=25` `(-5+5)(5/3a+b)+(5/3c+d)=25` `5/3C+d=25` `5C+3d=75-(2)` subtracting equation 1 from equation 2 `2C=18` `c=9` `c+d=19` `9+d=19` `d=10` Remainder=cx+d=9x+10. |
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