When a quantity of electricity is passed through `CuSO_(4)` solution 0.16 g of copper gets deposited if the same quantity of electricity is passed through acidullated water, then the volume of `H_(2)` gas liberated at S.T.P. will be (Given at wt. of Cu=64)A. `4.0cm^(3)`B. `56cm^(3)`C. `604cm^(3)`D. `8.0cm^(3)`

When a quantity of electricity is passed through `CuSO_(4)` solution 0

1.	When a quantity of electricity is passed through `CuSO_(4)` solution 0.16 g of copper gets deposited if the same quantity of electricity is passed through acidullated water, then the volume of `H_(2)` gas liberated at S.T.P. will be (Given at wt. of Cu=64)A. `4.0cm^(3)`B. `56cm^(3)`C. `604cm^(3)`D. `8.0cm^(3)`
Answer» Correct Answer - B `("Mass of Cu deposited")/("Volume of" H_("liberated"))=("Eq. wt of Cu")/("Eq. wt. of H")` `(0.18)/("Mass of" H_(2) "liberated")=(64//2)/(1)` or mass of `H_(2)` liberated `=(0.16)/(32)g=5xx10^(-3)g` `therefore` volume of `H_(2)` liberated at STP `=(22400)/(2)xx5xx10^(-3)cm^( 3)=56cm ^(3)`

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