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When a quantity of electricity is passed through `CuSO_(4)` solution, 0.16 g of copper gets deposited. If the same quantity of electricity is passed through acidulated water, then the volume of `H_(2)` liberated at STP will be : (given atomic weight of Cu=64)A. `4 cm^(3)`B. `56 cm^(3)`C. `604 cm^(3)`D. `8 cm^(3)` |
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Answer» Correct Answer - B Number of equivalents of copper deposited `=0.16/32=0.005` Volume of `H_(2)` gas at STP `=11.2xx0.005` `=0.056` litre `=56 cm^(3)` |
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