1.

When a rod of metal A is dipped in an aqueous solution of metal B (concentration of B^(2+) = 1M) at 25^(@)C , the electrode potentials are A^(2+) /A = -0.76 Volts, B = +0.343 Volts.

Answer»

A will gradually dissolve
B will DEPOSIT on A
No reaction will OCCUR
WATER will decompose into`H_2` and `O_(2)`

Solution : `E_(A//A^(2))^(@) + E_(B^(2) + B))^(@)= +ve`


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