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When a rubberball of volumeV, bulk modulus .K. is takento a depth .h.in water, thendecreasein itsvolume is |
Answer» SOLUTION : `B=(DELTAP)/((-(DELTAV)/(V)))` `-DeltaV=((DeltaP)V)/(K)` `=(h rho g V)/(K)` So decrease in VOLUMEOF ball `=(h rho g V)/(K)` |
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