1.

When a salt reacts with water to form acidic (or ) basic solution the process is called salt hydrolysis. The P^(H)of salt solution can be calculated using the following relation P^(H) =(1)/(2)[P^(k_w) +P^(Ka) + log C ] for salt of weak acid and strong base. P^(H)=(1)/(2)[P^(K_w) -P^(K_a) -log C ] for salt of weakbase and strong acid , P^(H) =(1)/(2)[P^(K_w) +P^(K_a) - P^(K_b) ] For a salt of weakacid and weakbase where .c. represents the concentration of salt . When a weak acid (or)a weak base is not completlyneatralised by strong base (or ) strong acid respectively, then formation of buffer takes places. The P^(H)of buffer solution can be calculated using the following relation P^(H)=P^(Ka) +log "" ((["salt")])/(["Acid "]) , P^(OH) =P^(Kb) +log ""(["salt"])/(["base"])Answer the following questions using the following data pK_a (CH_3COOH) =4.7447 , pK_b (NH_4OH) =4.7447 , P^(K_W)=14. One mole CH_3 COOHand one moleCH_3 COONa are dissolved in water one litre aqueous solution The P^(H)of the resulting solution will be

Answer»

` 9.2553`
` 4.7447 `
` 14`
` 7`

SOLUTION :`PH =PKA +log ""(S)/(A)=4.7447 +log ""(1)/(1) = 4.7447 `


Discussion

No Comment Found