1.

When a solution of NaCl containing C_(2)H_(5)OH is electrolysedit forms :

Answer»

`C Cl_(4)`
`CHI_(3)`
`CH_(2)Br_(2)`
`C_(2)H_(5)OH`

Solution :Chloroform is manufactured by electrolysis of an aqueous solution of ethyl alcohol and sodium chloride.
`NaCl(aq)rarr NA^(+)(aq)+Cl^(-)(aq)`
`H_(2)O rarr H^(+)+OH^(-)`
At cathode :
`Na^(+)(aq)+E^(-)rarr Na(s), "" E_("RED")^(@)=-2.71 V`
`2H_(2)O+2e^(-)rarr H_(2)(g)+2OH^(-)(aq), "" E_("red")^(@)=-0.83 V`
At cathode `H_(2)` gas is liuberated due to greater reduction potential of `H^(+)` than `Na^(+)`.
At anode :
`Cl^(-)rarr Cl+1e^(-)`
`Cl+Cl rarr Cl , E_(oxd.)^(@)=-1.36 V`
`H_(2)O(l)rarr 2H^(+)(aq)+1//2O_(2)(g), E_(oxd.)^(@)=-1.23 V`
At anode `Cl_(2)` is liberated due to over voltage
`C_(2)H_(5)OH+5Cl_(2)+H_(2)Orarr CHCl_(3)+CO_(2)+7HCl`


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