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When a source of frequency f_(0) moves away a stationary observer with a certain velocity an apparent frequency f' is observed. When it moves with same velocity towards the observer, the observed frequency is 1.2 f'. If velocity of sound in v, then the speed of source is - |
Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>)/(6)`<br/>`(v)/(<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)v`<br/>None of these</p>Solution :`f'=f_(0)((v)/(v+u)) and 1.2 f'=f_(0)((v)/(v-u))` <br/> `therefore1.2=(v+u)/(v-u)rArru=(v)/(11)`</body></html> | |