1.

When a voltage drop across a pn junction diode is increased from 0.70 V to 0.71V, the change in the diode current is 10 mA .What is the dynamic resistance of diode?

Answer»

For a p-n junction diode, the dynamic resistance is given by:

r = \(\frac{\Delta V}{\Delta I}\)

Given that:

ΔV = 0.71 - 0.70 = 0.01 V = 10-2 V

ΔI = 10-3 x 10 A = 10-2 A

\(\therefore\) r = \(\frac{10^{-2}}{10^{-2}}\) = 1 Ω.

Dynamic resistance =change in voltage/change in current=1 ohm.



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