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When a voltage drop across a pn junction diode is increased from 0.70 V to 0.71V, the change in the diode current is 10 mA .What is the dynamic resistance of diode? |
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Answer» For a p-n junction diode, the dynamic resistance is given by: r = \(\frac{\Delta V}{\Delta I}\) Given that: ΔV = 0.71 - 0.70 = 0.01 V = 10-2 V ΔI = 10-3 x 10 A = 10-2 A \(\therefore\) r = \(\frac{10^{-2}}{10^{-2}}\) = 1 Ω. Dynamic resistance =change in voltage/change in current=1 ohm. |
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