1.

When a white crystalline compound X is heated with K_(2)Cr_(2)O_(2) and concentrated H_(2)SO_(4) a reddish brown gas A is evolved. On passing A into caustic soda solution, a yellow coloured solution of B is obtained. Neutralizing the solution B with acetic acid and on subsequent addition of lead acetate, a yellow precipitate C is obtained. When X is heated with NaOH solution, a colourless gas is evolved and on passing this gas into KaHgle solution, a reddish brown precipitate D is formed. Identify A, B, C, D and X. Write the equations of reactions involved.

Answer»

Solution :`CrO_(2)`,`Na_(2)CrO_(4)`,`PbCrO_(4)`, iodide of Millon.s base `NH_(4)Cl`
`X = NH_(4)Cl`
`A = CrO_(2)Cl_(2)`
`B = Na_(2)CrO_(4)`
`C = PbCrO_(4)`
The chemical reactions are as FOLLOWS:
`Cr_(2)O_(7)^(-2)+4CI^(-)tounderset(A)underset("Raddish Brown")(2CrO_(2)CI_(2)uarr)+3H_(2)O`
`Cr_(2)O_(2)CI_(2)+4OH^(-)tounderset(B)underset("Yellow solution")(CrO_(4)^(-2))+2CI^(-)+2H_(2)O`
`Pb(OCOCH_(3))_(2)+CrO_(4)^(-2)tounderset(B)underset("Yellow ppt.")(PbCrO_(4))darr+2CH_(3)COO`
`NH_(4)^(+)+4OH^(-)+2[Hgl_(4)]^(-2)to`



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