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When a white crystalline compound X isheatedwith K_(2)Cr_(2)O_(7) andconcentratedH_(2)SO_(4) a reddishbrowngas A isevolved On passing A intosausticsodasolution ,ayellowcoloured solution of Bwith acetic B is obtained .Neutradiding thesolutionof B withaceticacid and onobtaijnedwhen Xof leadacetatewith NaOHsolutionprecipitate C isobtainedwhen Xis heatedwithNaOHsolutiona colouelessgas isevolvedand on passingthe gas into K_(2)HgI_(4) solution a reddishbrownprecipitate D isformedidentifyA,B,C and D and Xwritetheequationof thereactioninvolved. |
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Answer» SOLUTION :REACTIONS are as : Compound `X = NH_(4)CI,A = CrO_(2)CI_(2),B = Na_(2)CrO_(4),C = PbCrO_(4) ,D = NH_(2)(HGO)HgI + 3H_(2)O` i. `4NH_(4)CI(X) + K_(2)Cr_(2)O_(7) + 6H_(2)SO_(4) rarr 2CrO_(2)CI_(2)(A) + 4NH_(4)HSO_(4) + 2KHSO_(4)` ii `CrO_(2)CI_(2)(A) + 2NaOH rarr Na_(2)CrO_(4)(B) +2HCI` iii. `Na_(2)CrO_(4)(B) + (CH_(3)COO)_(2)Pb rarr PbCrO_(4)(C ) + 2CH_(3)COONa` iv. `NH_(4)CI + NaOH rarr NACI + NH_(3) +H_(2)O` v.`K_(2)HgI_(4) + NH_(3) + 3KOH rarr NH_(2)(HgO)HgI(D) + 7KI + 2H_(2)O` |
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