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When an alternating voltage E = Eosin ωt is applied to circuit, a current I = Iosin (ωt+π/2) flows through it. The average power dissipated in the circuit is :(a) Erms.Irms(b) EoIo(c) \(\frac{E_oI_o}{\sqrt2}\) (d) Zero |
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Answer» Option : (d) Zero |
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