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When an alternating voltage of `220 V` is applied across a device `P`, a current of `0.25 A` flows through the circuit and it leads the applied voltage by a angle `pi/2` radian. When the same voltage source is connected across another device `Q`, the same current is observed in the circuit but in phase with the applied voltage. What is the current when the same source is connected across a series combination of `P` and `Q`?A. 1/4`sqrt 2` A lagging in phase by `pi`/4 with voltageB. 1/4`sqrt 2` A leading in phase by `pi`/4 with voltageC. `1/sqrt 2`A leading in phase by `pi`/4 with voltageD. `1/sqrt 2` A leading in phase by `pi`/6 with voltage |
Answer» Correct Answer - B P is a capacitor, `X_C = 220 / 0.25 = 880 Omega` Q is resistance, `R = 220 / 0.25 = 880 Omega` When P and Q are in series, Z = `sqrt (R^(2) + X_C^(2))` = `880sqrt 2 Omega` `phi = tan^(-1)(X_C/R) = 45^(@)` (current leading ) `t = V / Z = 1 / 4sqrt 2` A |
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