When an electron in an excited state of Mo atom falls from L to K-shell, an X-ray is emitted. These X-rays are diffracted at angle of 7.75^@ by planes with a separation of 2.64 Å. What is the difference in energy between K-shell and L-shell in Mo, assuming a first order diffraction ? (sin 7.75^@ =0.1349)

When an electron in an excited state of Mo atom falls from L to K-shel

1.	When an electron in an excited state of Mo atom falls from L to K-shell, an X-ray is emitted. These X-rays are diffracted at angle of 7.75^@ by planes with a separation of 2.64 Å. What is the difference in energy between K-shell and L-shell in Mo, assuming a first order diffraction ? (sin 7.75^@ =0.1349)
Answer» Solution :According to BRAGG's equation : `n lambda =2 d SIN theta` `1 xx lambda=2xx2.64 sin 7.75^@ =2xx2.64 xx0.1349` `lambda`=0.712 Å Energy DIFFERENCE between K and L-shell of Mo=`"hc"/lambda=(6.626xx10^(-34)Js xx 3xx10^8 MS^(-1))/(0.712xx10^(-10)m)` `=2.791xx10^(-15) J`