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When an ideal gas expands in vaccum, there is neither absorption nor evolution of work ? Why ? |
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Answer» <P> SOLUTION :It is because no WORK is done.i.e., `w = 0 ""w = -p_(ext) XX Delta V = 0 xx Delta V = 0`. In `Delta U = q + w` q = 0 because the gas CHAMBER is insulated.`Delta U = 0 + 0 = 0`. |
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