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When an oxide of manganese (A) is fused with KOH in the presence of an oxidising agent and dissolved in water, it gives a dark green solution of compound (B). Compound (B) disproportionates in neutral or acidic solution to give purple compound (C). An alkaline solution of compound (C) oxidises potassium iodide solution to a compound (D) and compound (A) is also formed. Identify compounds (A) to (D) and also explain the reactions involved. |
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Answer» SOLUTION :The compounds (A), (B), (C) and (D) are given as under : (A) `MnO_(2)`(B) `K_(2)MnO_(4)`( C ) `KMnO_(4)`(D) `KIO_(3)` The reactions are EXPLAINED as under : `underset((A))(2MnO_(2))+4KOH+O_(2)to underset((B))(2K_(2)MnO_(4))+2H_(2)O` `3MnO_(4)^(2-)+4H^(+)to underset((C))(2MnO_(4)^(-))+MnO_(2)+2H_(2)O` `2MnO_(4)^(-)+H_(2)O+KI to underset((A))(2MnO_(2))+2OH^(-)+underset((D))(KIO_(3))` |
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