When any solution passes through a cation exchange resin that is in acidic form, H^(+) ion of the solution. A solution containing 0.319 g of an isomer with molecular formula CrCl_(3).6H_(2)O is passed through a cation exchange resin in acidic form. The diluted solution requires 19cm^(3) of 0.125 N NaOH. The isomer is :

When any solution passes through a cation exchange resin that is in ac

1.	When any solution passes through a cation exchange resin that is in acidic form, H^(+) ion of the solution. A solution containing 0.319 g of an isomer with molecular formula CrCl_(3).6H_(2)O is passed through a cation exchange resin in acidic form. The diluted solution requires 19cm^(3) of 0.125 N NaOH. The isomer is :
Answer» triaquatrichlorochrominum (III) chloride trihydrate hexaaquachromium (III) chloride pentaaquamonochlorochromium (III) chloride monohydrate tetraaquadichlorochromium (III) chloride dihydrate Solution :`CrCl_(3).6H_(2)Oto` diluted solution requires 19 mm and 0.125N NaOH=2.375 m mole `OH^(-)` `0.319/266.5 = 0.00119` `CrCl_(3).6H_(2)O to 0.00119` mole, `[Cr(H_(2)O)_(5)Cl]Cl_(2).H_(2)Oto 2CL^(-)to 2H^(+)` `2H^(+)` requires `to 2OH^(-)` `0.00119 xx 2` MOLES of `Cl^(-1)=nH^(+)` `1000 xx 0.00238`=2.38 moles