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When BCl_3 is treated with water, it hydrolyses and forms [B(OH)_4]^(-)only whereas AlCl_3 in acidifiedaqueous solution forms [Al(H_2O)_6]^(3+) ion. Explain what is the hybridizations of boron and aluminium in these species ? |
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Answer» Solution :In trivalent state , most of COMPOUNDS being cavlent are hydrolyzed in water . For example ,the trichorides on hydrolysis in water form tetrahedral `[M(OH)_4]` species , the hybridizationstate of element M is `sp^3` . `BCl+ 3H_2O to B(OH)_3 + 3HCl` `B(OH)_3 + H_2O to [B(OH)_4]^(-) + H^(+)` Aluminum chloride in ACIDIFIED aqueous solution forms OCTAHEDRAL `[AL(H_2O)_6]^(+3)`ion. In this complex ion, the 3d-orbitals of Al are involved and the hybridizations state of Al is `sp^3d^2`. `AlCl_3 + H_2O overset(HCl)to [Al(H_2O)_6]^(3+) + 3Cl^(-)`
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