1.

When CH_(2) = CH - COOH is reduced with LiAlH_(4), the compound obtained will be

Answer»

`CH_(3) - CH_(2) - COOH`
`CH_(2) = CH - CH_(2)OH`
`CH_(3)CH_(2) - CH_(2)OH`
`CH_(3) - CH_(2) - CHO`

Solution :When `CH_(2) = CH - COOH` is reduced with `LiAlH_(4) : CH_(2) = CH - CH_(2)OH` COMPOUND is formed because `LiAlH_(4)` reduces `-COOH` to `CH_(2)OH` WITHOUT affecting `C = C` BOND


Discussion

No Comment Found