When CI_(2) gas reacts with hot and concentrated sodium hydroxide solution the oxidation number of chlorine changes from

When CI_(2) gas reacts with hot and concentrated sodium hydroxide solu

1.	When CI_(2) gas reacts with hot and concentrated sodium hydroxide solution the oxidation number of chlorine changes from
Answer» zero to +1 and zero to -5 zero to -1 and zero to +5 zero to -1 and zero +3 zero to +1 and zero to -3 Solution :`3overset(+1)CIOrarroverset(+5)CIO_(3)^(-)+2overset(-1)CI^(-)` Here O.N of CI increases from +1 CIO to +5 in `CIO_(3)^(-)` while that of CI decrease form +1 in `CIO_(3)^(-)` while that of CI DECRESES form +1 in `CIO^(-)` to -1 `CI^(-)` THEREFORE it is a disproportionation REACTION